HI,
Just to add:
res<-do.call(c,lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x)
{names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y)
read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))})) #it seems like
one of the rows of your file doesn't have 6 elements, so added fill=TRUE
names(res)<-paste("group_",gsub("\\d+","",names(res)),sep="")
res[grep("group_b",names(res))]
I am not sure how you want the grouped data to look like. If you want
something like this:
res1<-do.call(rbind,res)
res2<-lapply(split(res1,gsub("[.0-9]","",row.names(res1))),function(x)
{row.names(x)<-1:nrow(x);x})
res2
#$group_a
# Id M mm x b u k j y p v
#1 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#2 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#3 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#4 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#5 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#6 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#7 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#8 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#9 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#10 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#11 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#12 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#13 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#14 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#15 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#16 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#17 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#18 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#$group_b
# Id M mm x b u k j y p v
#1 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#2 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#3 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#4 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#5 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#6 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#7 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#8 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#9 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#10 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#11 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#12 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#$group_c
# Id M mm x b u k j y p v
#1 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#2 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#3 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#4 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#5 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#6 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#or if you want it like this:
res2<-split(res,names(res))
res2[["group_b"]]
#$group_b
# Id M mm x b u k j y p v
#1 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#2 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#3 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#4 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#5 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#6 AA na 2 1972 0.0007000 11 3 AR 25 509 734
#$group_b
# Id M mm x b u k j y p v
#1 aAA 1 2 739 0.1257000 2 2 AA 2 8867 8926
#2 aAAAA 1 2 2263 0.0004000 2 2 AR 4 7640 8926
#3 aA 2 1 1 0.0845435 2 AA 2 6790 734,1092 NA
#4 aAA 1 2 1965 0.0007000 4 3 AR 2 11616 8926
#5 aAAA 1 3 3660 0.0008600 18 3 AA 2 20392 496
#6 AA na 2 1972 0.0007000 11 3 AR 25 509 734
Hope this helps.
A.K.
----- Original Message -----
From: "veracosta...@gmail.com" <veracosta...@gmail.com>
To: smartpink...@yahoo.com
Cc:
Sent: Friday, February 15, 2013 9:15 AM
Subject: reading data
Hi,
I post yesterday and you helped me. I have little problem.
At first, I never worked with regular expressions...
The code that you gave me it's ok, but my files are inside the folders
a1,a2,a3. I try to explain better.
I have one folder named "data". Inside this folder I have some other folders
named "a1","a2","b1",b2",...and inside of each one of that I have some files. I
want only the file "mmmmmm.txt" (in all folders I have One file with this name).
The name of the folder give me the name of the group,but I need to read the
file inside. And after, have "group_a", group_"b"...because I need to work with
this data grouped (and know the name of the group).
Thank you.
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