Hello,

Sorry, there's a bug in my first reply. Corrected:


fun <- function(x, y){
        df3 <- cbind(x, y[setdiff(names(y), names(x))])
        df3[order(names(df3))]
}
fun(df1, df2)

Rui Barradas

Em 07-02-2013 19:16, Rui Barradas escreveu:
Hello,

The following function will give what you seem to want.


fun <- function(x, y){
     df3 <- x
     df3 <- cbind(df3, df2[setdiff(names(y), names(x))])
     df3[order(names(df3))]
}

fun(df1, df3)



Hope this helps,

Rui Barradas

Em 07-02-2013 18:36, Anika Masters escreveu:
#I have 2 dataframes df1 & df2.  Each has a subset of all possible
column names.
#How do I combine the 2 tables so that they contain all column names?

data1 <- c('2','3', '6', '8' , '9')
data2 <- c('1', '2', '3', '6')
df1 <- data.frame(matrix(data=NA, nrow=1, ncol=length(data1),
dimnames=list(NULL, paste('col', data1, sep='') ) ) )
df2 <- data.frame(matrix(data=data2, nrow=1, ncol=length(data2),
dimnames=list(NULL, paste('col', data2, sep='') ) ) )

e.g.
data1 <- c('2','3', '6', '8' , '9')
data2 <- c('1', '2', '3', '6')
df1 <- data.frame(matrix(data=NA, nrow=1, ncol=length(data1),
dimnames=list(NULL, paste('col', data1, sep='') ) ) )
df2 <- data.frame(matrix(data=data2, nrow=1, ncol=length(data2),
dimnames=list(NULL, paste('col', data2, sep='') ) ) )

#I want:
names3 <- sort( unique(c(names(df1), names(df2) ) ) )
df3 <- data.frame(matrix(data=c('1','2','3','6','8','9'), nrow=1,
ncol=length(names3), dimnames=list(NULL, names3 ) ) )

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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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and provide commented, minimal, self-contained, reproducible code.

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