On Feb 4, 2013, at 9:48 AM, Steven Ranney wrote:
> I have a large data frame ("data1") that looks like:
>
> A1 A2 A3 A4 A5 A6 A7 A8 A9 A10 A11 A12 A13 A14 A15 A16 A17 A18 A19 A20
> [1,] 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0
> [2,] 0 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 0 0 0 0
> [3,] 1 1 0 1 1 1 1 1 1 1 1 0 1 1 0 0 0 0 0 0
> [4,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 0 0 2
> [5,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 2 0 2
> [6,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 2 2 2
> [7,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [8,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [9,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [10,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [11,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [12,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [13,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [14,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [15,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [16,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2
> [17,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2
> [18,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2
> [19,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 2 2
> [20,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [21,] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
> [22,] 0 0 0 2 0 0 0 0 0 0 0 2 0 0 0 1 0 0 0 0
> [23,] 0 0 0 2 0 0 0 1 0 0 0 2 0 0 0 2 0 0 0 2
> [24,] 0 0 1 2 0 0 0 2 0 0 1 1 0 1 0 1 0 0 2 2
> [25,] 0 1 1 2 0 2 2 2 1 1 1 1 0 1 1 1 1 0 2 2
> [26,] 1 1 1 1 1 2 2 2 1 1 1 1 2 1 1 1 1 2 2 2
> [27,] 1 1 1 1 1 2 1 2 1 1 1 1 2 1 1 1 1 2 2 2
> [28,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [29,] 1 1 1 1 1 1 1 2 1 1 1 1 1 1 2 1 1 2 2 2
> [30,] 1 1 1 2 1 1 1 2 1 1 1 1 1 1 1 2 1 2 2 2
> [31,] 1 1 2 1 1 1 1 1 1 1 1 1 2 2 1 1 1 2 2 2
> [32,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [33,] 1 1 1 1 1 3 3 3 3 1 3 3 1 1 2 1 1 2 2 2
> [34,] 1 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 2 2 2
> [35,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2
> [36,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [37,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2
> [38,] 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0
> [39,] 0 0 0 0 0 0 0 0 0 2 0 0 2 0 0 2 0 0 0 2
> [40,] 1 1 2 1 1 2 1 2 2 2 2 2 2 1 1 1 1 2 3 2
>
> (data1 is actually 1,080 rows long.)
>
> If there is a "3" in any row above, I'd like to be given the values
> from a second data frame ("meter"):
>
> meter
> 1 20
> 2 19
> 3 18
> 4 17
> 5 16
> 6 15
> 7 14
> 8 13
> 9 12
> 10 11
> 11 10
> 12 9
> 13 8
> 14 7
> 15 6
> 16 5
> 17 4
> 18 3
> 19 2
> 20 1
> 21 20
> 22 19
> 23 18
> 24 17
> 25 16
> 26 15
> 27 14
> 28 13
> 29 8
> 30 7
> 31 6
> 32 2
> 33 1
> 34 10
> 35 4
> 36 3
> 37 2
> 38 18
> 39 17
> 40 15
>
> (meter is actually 1,080 rows long)
One hopes for the success of htis effort that 'data1' has an equal number of
rows.
>
> If there is no "3" row i of data1, I'd like to R to return "NA".
>
> I've tried
>
> for(i in 1:40){
> if(
> }
>
Generally sequential testing is best handled with `ifelse` rather than with for
loops and `if () {} else{}`
mA <- ifelse ( apply(data, 1, any), meter, NA)
> But I'm given:
>
>> mA
> [1] 15
> Levels: 1 10 11 12 13 14 15 16 17 18 19 2 20 3 4 5 6 7 8 9
The fact that you have constructed a factor variable suggest that you made an
error in building the 'meter' data and that is it no numeric at the moment. The
fact that it is only length = 1 is due to your not indexing the construction of
'mA' in your loop.
>
> Can anyone give me some additional ideas to try?
>
> Thanks -
>
David Winsemius
Alameda, CA, USA
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
