You can also try 'mapply'
> aa<-list(c(1:3), c(4:6))
> bb<-list(3,5)
> mapply(setdiff, aa, bb)
[,1] [,2]
[1,] 1 4
[2,] 2 6
>
On Fri, Feb 1, 2013 at 5:16 AM, Simone Gabbriellini
<simone.gabbriell...@gmail.com> wrote:
> Dear List,
>
> I have a data structure like:
>
>> aa
> [[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
>
>> bb
> [[1]]
> [1] 3
>
> [[2]]
> [1] 5
>
> I would like to set differences between "aa" and "bb" and get as
> result another list of lists like:
>
>> res
> [[1]]
> [1] 1 2
>
> [[2]]
> [1] 4 6
>
> I am trying:
>
> lapply(aa, setdiff, bb)
>
> but I simply get "aa" back as result. Could you please point me in the
> right direction about the combination of functions that I need to
> accomplish this task?
>
> Best regards,
> Simone
>
> --
> Simone Gabbriellini, PhD
>
> PostDoc@DISI, University of Bologna
> mobile: +39 340 39 75 626
> email: simone.gabbriell...@unibo.it
> home: www.digitaldust.it
>
> DigitalBrains srl
> Amministratore
> mobile: +39 340 39 75 626
> email: simone.gabbriell...@digitalbrains.it
> home: www.digitalbrains.it
>
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--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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