try this:
> x <- read.table(text = " No. Change Date
+ A 123 final 2013-01-15
+ B 123 error 2013-01-16
+ C 123 'bug fixed' 2013-01-17
+ D 111 final 2013-01-12"
+ , header = TRUE
+ , as.is = TRUE
+ )
> do.call(rbind, lapply(split(x, x$No.), function(.sec){
+ .sec[which(.sec$Date == max(.sec$Date))[1L], ]
+ }))
No. Change Date
111 111 final 2013-01-12
123 123 bug fixed 2013-01-17
On Fri, Feb 1, 2013 at 3:04 AM, Mat <matthias.we...@fnt.de> wrote:
> Hello together,
>
> i have a data.frame, like this one:
> No. Change Date
> A 123 final 2013-01-15
> B 123 error 2013-01-16
> C 123 bug fixed 2013-01-17
> D 111 final 2013-01-12
>
> and now a want a new data.frame which includes only the newest entry for
> each number.
> The solution look like this:
> No. Change Date
> C 123 bug fixed 2013-01-17
> D 111 final 2013-01-12
>
> is there any way to filter my data.frame to the latest data, perhabs "max"?
>
> Thanks.
>
> Mat
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Filter-according-to-the-latest-data-tp4657248.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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