Dear Barry, thank you very much for this information. This looks pretty interesting!
Best Simon On Jan 31, 2013, at 4:09 PM, Barry Rowlingson <b.rowling...@lancaster.ac.uk> wrote: >> it lets you do: >> >> (a~b~c) = foo() > > Mistook. should be: > > (a~b~c) %=% foo() > > because it defines the %=% operator. > > Barry ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
