Hi, Benjamin,
have you tried for your list with NA-components to use is.na() as follows
(where x is assumed to be your list)?
x[ !is.na(x)]
Hth -- Gerrit
On Tue, 29 Jan 2013, Benjamin Ward (ENV) wrote:
Hi, This is probably a small query but one I'm struggling with: I have a
list in which I had elements which were NA, I removed them, by doing:
list2 <- lapply(list, na.omit),
However this leaves the element there with 'character(0)' in place as
well as attributes:
e.g.
[[978]]
character(0)
attr(,"na.action")
[1] 1
attr(,"class")
[1] "omit"
I want to get rid of these elements/positions in the list, since a
function is supposed to sample the list for elements (each element is a
collection of about 20 numbers each).
Thanks,
Ben W.
UEA (ENV) - b.w...@uea.ac.uk
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