Thanks a million for all help provided!! I can do what I intend to using
the "for loop". However, I'm still eager to try the list.files approach.
Here is the error message that I got using Ivan's code:

> list_of_dataset <- do.call(read.table, file_names)
Error in do.call(read.table, file_names) : second argument must be a list

Please advise.

Ray

On Sun, Jan 27, 2013 at 10:57 PM, Ivan Calandra <
ivan.calan...@u-bourgogne.fr> wrote:

>  Hi Ray!
>
> I'm insisting with list.files...!
>
> What about like this (untested)?
> file_names <- list.files(path="C:/.../data", pattern=".dat$",
> full.names=TRUE)
> list_of_dataset <- do.call(read.table, file_names)
>
> Let me know if this helps!
> Ivan
>
> --
> Ivan CALANDRA
> Université de Bourgogne
> UMR CNRS/uB 6282 Biogéosciences
> 6 Boulevard Gabriel
> 21000 Dijon, FRANCE+33(0)3.80.39.63.06ivan.calan...@u-bourgogne.fr
> http://biogeosciences.u-bourgogne.fr/calandra
>
> Le 26/01/13 10:03, Ray Cheung a écrit :
>
> Thanks for your commands, Ivan and Michael! However, I am still not
> producing the right codes. Would you please help me on this? I've written
> the following codes. Please comment. Thank you very much.
>
> Task: Reading data1.dat to data1000.dat (with missing files) into R.
> Missing files can be omitted in the list.
>
> ###FUNCTION TO READ FILES
> little_helpful <- function(n) {
> file_name <- paste0("C:/.../data", n, ".dat")
> read.table(file_name)
> }
>
> ###RETURN AN OBJECT WHICH CHECKS FOR THE EXISTENCE OF FILES
> check  <- function(n) {
> a <- ifelse(file.exists(paste0("C:/.../data", n, ".dat")), 1, 0)
> a
> }
>  ###Combining the functions
> IMPORT <- function(n) {
>    L <- check(1:n)
>    for (i in 1:n) {
>       if (L[i] == 1)
>       list_of_datasets <- lapply(i, little_helpful) else list_of_datasets
> <- 0
>       }
>    list_of_datasets
>    }
>
> Thanks for all comments.
>
> Best Regards,
> Ray
>
>  On Fri, Jan 25, 2013 at 5:48 PM, Ivan Calandra <
> ivan.calan...@u-bourgogne.fr> wrote:
>
>> Hi,
>>
>> Not sure this is what you need, but what about list.files()?
>> It can get you all the files from a given folder, and you could then work
>> this list with regular expressions for example.
>>
>> HTH,
>> Ivan
>>
>> --
>> Ivan CALANDRA
>> Université de Bourgogne
>> UMR CNRS/uB 6282 Biogéosciences
>> 6 Boulevard Gabriel
>> 21000 Dijon, FRANCE
>> +33(0)3.80.39.63.06
>> ivan.calan...@u-bourgogne.fr
>> http://biogeosciences.u-bourgogne.fr/calandra
>>
>> Le 25/01/13 10:00, R. Michael Weylandt a écrit :
>>
>>>  On Fri, Jan 25, 2013 at 6:11 AM, Ray Cheung <ray1...@gmail.com> wrote:
>>>
>>>> Dear Michael,
>>>>
>>>> Thanks for your codes. However, lapply does not work in my case since
>>>> I've
>>>> some files missing in the data (say, the file data101.dat). Do you have
>>>> any
>>>> suggestions on this?? Thank you very much.
>>>>
>>>>  You could simply add a test using file.exists() but I'm not sure what
>>> you want to do with the M matrix then -- omit the slice (so the others
>>> are all shifted down one) or fill it entirely with NA's.
>>>
>>> Michael
>>>
>>>   ______________________________________________
>>> R-help@r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>

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