Hi Yasha,
I guess you got Uwe's response.
I created `df2` with the intention of getting the two results from the
original dataset.
For example, after you get the first result
df[,1][grep("@",df$names)]<- ""
#you can get the second result by:
df[df$names!="",]
# names emails
#1 bob b...@cup.com
#2 joe joesm...@gmail.com
#4 emily emi...@yahoo.com
#or
df[grep("\\w+",df$names),]
# names emails
#1 bob b...@cup.com
#2 joe joesm...@gmail.com
#4 emily emi...@yahoo.com
But, I am not sure how this will work over a 5.5 million rows.
A.K.
----- Original Message -----
From: ypodeswa <ypode...@gmail.com>
To: r-help@r-project.org
Cc:
Sent: Sunday, January 27, 2013 1:11 AM
Subject: Re: [R] Removing values containing a specific character
Actually, it worked perfectly for my sample data, but my actual data has
5.5 million rows, and grep doesn't seem to work with over a million rows.
Any idea on a workaround?
On Sat, Jan 26, 2013 at 9:37 PM, Yasha Podeswa <ypode...@gmail.com> wrote:
> Awesome, thanks Arun, that's exactly what I was looking for!
>
>
> On Sat, Jan 26, 2013 at 9:21 PM, arun kirshna [via R] <
> ml-node+s789695n4656749...@n4.nabble.com> wrote:
>
>> Hi,
>> Try this:
>> df[]<-lapply(df,as.character)
>> df2<-df
>> df[,1][grep("@",df$names)]<- ""
>> df
>> #names emails
>> #1 bob b...@cup.com
>> #2 joe joesm...@gmail.com
>> #3 cr...@gmail.com
>> #4 emily emi...@yahoo.com
>> #5 j...@yahoo.com
>>
>> #2nd part:
>>
>> df2[-grep("@",df2$names),]
>> names emails
>> #1 bob b...@cup.com
>> #2 joe joesm...@gmail.com
>> #4 emily emi...@yahoo.com
>> A.K.
>>
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