Hi,
Your question is bit confusing to me.
When you say that "which rrts are the same, and which are the new ones", to
me it looks like "0.35, 0.36" are new addition to Mnd at time points 6 and 9.
Extending Dennis' solution:
Just for understanding the problem:
vec1<-c(0.45,0.48,1.24,1.22,0.44,0.46,1.21)
dat$newCol<-ifelse(dat$rrt%in%vec1,"old","new")
dcast(dat,Time+newCol~Mnd,value.var="Result")
# Time newCol 0 3 6 9
#1 0.3550 new NA NA 0.05 0.06
#2 0.4475 old 0.1 0.2 0.40 0.60
#3 0.4750 old 0.3 0.6 1.20 1.80
#4 1.2225 old 0.5 0.4 0.45 0.50
A.K.
----- Original Message -----
From: Bart Joosen <bartjoo...@hotmail.com>
To: Dennis Murphy <djmu...@gmail.com>; r-help@r-project.org
Cc:
Sent: Friday, January 25, 2013 1:48 AM
Subject: Re: [R] sorting/grouping/classification problem?
Nice suggestion for the extra "Time" column.
But I think I didn't ask clear enough my problem.
My main problem is to find a way to "classify" the rrt's, so that we don't have
to check each dataframe by our selfs.
So I need a function that fills in the extra "Time" column by taking a look at
the rrt's (and maybe the results), and take the discision which rrts are the
same, and which are new ones.
As stated: rrt's never switch place, and results can't be concatenated or
averaged within a Mnd.
I hope my question is a bit more clear now.
Thank you all for your suggestions
Bart
> Date: Thu, 24 Jan 2013 15:01:40 -0800
> Subject: Re: [R] sorting/grouping/classification problem?
> From: djmu...@gmail.com
> To: bartjoo...@hotmail.com
>
> Hi:
>
> Here's a potential workaround:
>
> # Add a time order variable
> dat$ord <- c(rep(2:4, 2), rep(1:4, 2))
>
> # Average rrt by ord
> dat$Time <- with(dat, ave(rrt, ord, FUN = mean))
> dat
>
> # Reshape the data
>
> library(reshape2)
> > dcast(dat, Time ~ Mnd, value.var = "Result")
> Time 0 3 6 9
> 1 0.3550 NA NA 0.05 0.06
> 2 0.4475 0.1 0.2 0.40 0.60
> 3 0.4750 0.3 0.6 1.20 1.80
> 4 1.2225 0.5 0.4 0.45 0.50
>
> You could always round dat$Time to two decimal places in its
> definition before doing the cast if you so desired.
>
> Dennis
>
> On Thu, Jan 24, 2013 at 11:31 AM, Bart Joosen <bartjoo...@hotmail.com> wrote:
> >
> > Hi,
> >
> >
> > I'm a database admin for a database which manage chromatographic results of
> > products during stability studies.
> > I use R for the reporting of the results in MS Word through R2wd.
> >
> >
> > But now I think I need your help:
> > suppose we have the following data frame:
> >
> >
> > ID rrt Mnd Result
> > 1 0.45 0 0.10
> > 1 0.48 0 0.30
> > 1 1.24 0 0.50
> > 2 0.45 3 0.20
> > 2 0.48 3 0.60
> > 2 1.22 3 0.40
> > 3 0.35 6 0.05
> > 3 0.44 6 0.40
> > 3 0.46 6 1.20
> > 3 1.21 6 0.45
> > 4 0.36 9 0.06
> > 4 0.45 9 0.60
> > 4 0.48 9 1.80
> > 4 1.22 9 0.50
> >
> >
> >
> > ID is the database ID, rrt is an identifier for the result, Mnd is the
> > timepoint of analysis and Result is... the result of the test.
> > What I need is this dataframe in a wide format (which I managed with dat2
> > <- as.data.frame(tapply(dat$Result,list(rrt=dat$rrt,Mnd=dat$Mnd),
> > function(x) paste(x[x!=""],collapse="/"))) )
> > But as you can see, rrt is not an exact identifier for the result.
> >
> > Sometimes rrt for 0 Mnd is 0.45, but at 6 Mnd the rrt is 0.44.
> > Now I need the results to align so that one can easily see how rrt x is
> > evolving within the Mnd time points.
> > I tried with different rounding procedures (round every 0.02, check that no
> > results are discarded this way, and check for alignment), but nothing seems
> > to make some sense.
> > Also tried checking the highest results in each Mnd, align these, determine
> > correction factors for the rrt for all the other rrts, ...
> >
> >
> > Some results will follow a trend (like rrt 0.45), some will remain more or
> > less stable.
> > But NEVER rrt will switch i with each other!
> >
> >
> >
> >
> > Ultimately I need to update in the db, so I need a list/dataframe with the
> > ID, the original rrt and the adjusted rrt (maybe the first occuring rrt, or
> > the mean of the rrts, doesn't matter).
> >
> >
> >
> >
> > Any ideas about which algorithms can be used? I searched on pubmed, but
> > couldn't find anything
> >
> >
> >
> >
> > Thanks
> >
> >
> > Bart
> >
> >
> > PS: to get the data:
> >
> >
> > dat <-
> > structure(list(ID = c(1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L, 3L,
> > 4L, 4L, 4L, 4L), rrt = c(0.45, 0.48, 1.24, 0.45, 0.48, 1.22,
> > 0.35, 0.44, 0.46, 1.21, 0.36, 0.45, 0.48, 1.22), Mnd = c(0L,
> > 0L, 0L, 3L, 3L, 3L, 6L, 6L, 6L, 6L, 9L, 9L, 9L, 9L), Result = c(0.1,
> > 0.3, 0.5, 0.2, 0.6, 0.4, 0.05, 0.4, 1.2, 0.45, 0.06, 0.6, 1.8,
> > 0.5)), .Names = c("ID", "rrt", "Mnd", "Result"), class = "data.frame",
> > row.names = c(NA,
> > -14L))
> >
> >
> >
> > resulting dataframe:
> > dat3 <-
> > structure(list(Time = c(0.355, 0.45, 0.48, 1.22), `0` = c(NA,
> > 0.1, 0.3, 0.5), `3` = c(NA, 0.2, 0.6, 0.4), `6` = c(0.05, 0.4,
> > 1.2, 0.45), `9` = c(0.06, 0.6, 1.8, 0.5)), .Names = c("Time",
> > "0", "3", "6", "9"), class = "data.frame", row.names = c(NA,
> > -4L))
> >
> >
> >
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
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and provide commented, minimal, self-contained, reproducible code.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
