This idea is very simple and helpful. But one has to start with 0.05.
Thanks.
test.df$n<- seq(0.05,1, by=0.05)
2013/1/24 Rui Barradas <ruipbarra...@sapo.pt>
> Hello,
>
> try the following.
>
> test.df$Var1 <- seq(0,1, by=0.05)[-1]
> test.df
>
>
> Hope this helps,
>
> Rui Barradas
>
> Em 24-01-2013 17:39, Wim Kreinen escreveu:
>
>> Hello,
>>
>> I have a dataframe (test.df) with intervals that were generated by table
>> (see below). I would prefer a dataframe labeled like this:
>>
>>
>> test.tab <- table(cut(skn.test$density, seq (0,1, by=0.05)))
>>> test.tab
>>>
>>
>> (0,0.05] (0.05,0.1] (0.1,0.15] (0.15,0.2] (0.2,0.25] (0.25,0.3]
>> (0.3,0.35]
>> 68 87 85 72 65 73
>> 74
>> (0.35,0.4] (0.4,0.45] (0.45,0.5] (0.5,0.55] (0.55,0.6] (0.6,0.65]
>> (0.65,0.7]
>> 72 77 78 75 74 83
>> 93
>> (0.7,0.75] (0.75,0.8] (0.8,0.85] (0.85,0.9] (0.9,0.95] (0.95,1]
>> 89 75 67 59 56 208
>>
>>> test.df <- as.data.frame (test.tab)
>>> test.df
>>>
>> Var1 Freq
>> 1 (0,0.05] 68
>> 2 (0.05,0.1] 87
>> 3 (0.1,0.15] 85
>> 4 (0.15,0.2] 72
>> 5 (0.2,0.25] 65
>> 6 (0.25,0.3] 73
>> 7 (0.3,0.35] 74
>> ....
>>
>>
>> I would prefer a dataframe labelled like this.
>> 0.05 68
>> 0.1 87
>>
>>
>> How to do?
>> Thanks
>> Wim
>>
>>
>> dput (test.tab)
>>>
>> structure(c(68L, 87L, 85L, 72L, 65L, 73L, 74L, 72L, 77L, 78L,
>> 75L, 74L, 83L, 93L, 89L, 75L, 67L, 59L, 56L, 208L), .Dim = 20L, .Dimnames
>> =
>> structure(list(
>> c("(0,0.05]", "(0.05,0.1]", "(0.1,0.15]", "(0.15,0.2]", "(0.2,0.25]",
>> "(0.25,0.3]", "(0.3,0.35]", "(0.35,0.4]", "(0.4,0.45]", "(0.45,0.5]",
>> "(0.5,0.55]", "(0.55,0.6]", "(0.6,0.65]", "(0.65,0.7]", "(0.7,0.75]",
>> "(0.75,0.8]", "(0.8,0.85]", "(0.85,0.9]", "(0.9,0.95]", "(0.95,1]"
>> )), .Names = ""), class = "table")
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________**________________
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>> PLEASE do read the posting guide http://www.R-project.org/**
>> posting-guide.html <http://www.R-project.org/posting-guide.html>
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
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