Hi,
Not sure what format you wanted the dates:
gsub("^\\w+ ","",gsub("[_]"," ",Text))
#[1] "May 09 2009" "01-01-2001"
#Another way is:
gsub("^\\w+ |\\w+_","",Text)
#[1] "May 09 2009" "01-01-2001"
res<- gsub("^\\w+ |\\w+_","",Text)
res1<-c(as.Date(res[grep(" ",res)],format="%b %d %Y"), as.Date(res[-grep("
",res)],format="%m-%d-%Y"))
res1
#[1] "2009-05-09" "2001-01-01"
A.K.
----- Original Message -----
From: Christofer Bogaso <bogaso.christo...@gmail.com>
To: r-help <r-help@r-project.org>
Cc:
Sent: Friday, January 18, 2013 3:11 PM
Subject: [R] Working with regular expression
Hello again,
I was trying to extract the date element from a character vector using
Regular expression. Below is a sample what I was trying to do:
> Text <- c("asdf May 09 2009", "dsaf_01-01-2001")
> gsub("[a-zA-Z_]", "", Text)
[1] " 09 2009" "01-01-2001"
I basically have a long text and the task is to extract the date
element. My above strategy failed because I can not extract the month
for the first element.
Can somebody help me out?
Thanks and regards,
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
