Hello,
Continuing Jessica's code, to get the maximum of each group just use
b <- c(1,1,1,2,3,4,3,2,1,1,1,1,1,2,3,4,5,4,3.5,3,2,1,1,1)
r <- rle(b > 1)
groups <- rep(1:length(r$lengths),r$lengths)
tapply(b, groups, FUN = max)
# To get just the groups where b > 1,
mx <- tapply(b, groups, FUN = max)
mx[mx > 1]
# And you can combine both like in
cbind(length = r$lengths[r$values], max = mx[mx > 1])
Hope this helps,
Rui Barradas
Em 15-01-2013 16:57, Jessica Streicher escreveu:
Maybe rle can help a little here
rle(b>1)
Run Length Encoding
lengths: int [1:5] 3 5 5 8 3
values : logi [1:5] FALSE TRUE FALSE TRUE FALSE
r<-rle(b>1)
r$lengths[r$values]
[1] 5 8
# started for the maximum but need to go home now, sorry. Will continue
tomorrow if noone else finishes it.
groups <- rep(1:length(r$lengths),r$lengths)
On 15.01.2013, at 17:16, Benjamin Gillespie wrote:
Hi all,
Thanks in advance for any help.
I have a vector "b":
b=c(1,1,1,2,3,4,3,2,1,1,1,1,1,2,3,4,5,4,3.5,3,2,1,1,1)
Imagine b is river flow throughout time.
I would like some code that will generate the following information:
number of individual 'periods' where b>1 (= 2 in this case)
period 1 length = 5, max = 4
period 2 length = 8, max = 5
I can't figure anything useful out.
Thanks,
Ben Gillespie
Research Postgraduate
School of Geography
University of Leeds
Leeds
LS2 9JT
http://www.geog.leeds.ac.uk/
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