Hello,

Continuing Jessica's code, to get the maximum of each group just use

b <- c(1,1,1,2,3,4,3,2,1,1,1,1,1,2,3,4,5,4,3.5,3,2,1,1,1)
r <- rle(b > 1)
groups <- rep(1:length(r$lengths),r$lengths)

tapply(b, groups, FUN = max)

# To get just the groups where b > 1,

mx <- tapply(b, groups, FUN = max)
mx[mx > 1]

# And you can combine both like in

cbind(length = r$lengths[r$values], max = mx[mx > 1])


Hope this helps,

Rui Barradas
Em 15-01-2013 16:57, Jessica Streicher escreveu:
Maybe rle can help a little here

rle(b>1)

Run Length Encoding
   lengths: int [1:5] 3 5 5 8 3
   values : logi [1:5] FALSE TRUE FALSE TRUE FALSE

  r<-rle(b>1)

r$lengths[r$values]
[1] 5 8

# started for the maximum but need to go home now, sorry. Will continue 
tomorrow if noone else finishes it.
groups <- rep(1:length(r$lengths),r$lengths)

On 15.01.2013, at 17:16, Benjamin Gillespie wrote:

Hi all,

Thanks in advance for any help.

I have a vector "b":

b=c(1,1,1,2,3,4,3,2,1,1,1,1,1,2,3,4,5,4,3.5,3,2,1,1,1)

Imagine b is river flow throughout time.

I would like some code that will generate the following information:

number of individual 'periods' where b>1 (= 2 in this case)
period 1 length = 5, max = 4
period 2 length = 8, max = 5

I can't figure anything useful out.

Thanks,
                
Ben Gillespie
Research Postgraduate

School of Geography
University of Leeds
Leeds
LS2 9JT

http://www.geog.leeds.ac.uk/
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