HI,
str1<-"x$Expensive"
regexpr("\\$",str1)[1]
#[1] 2
str2<-"x$Exp$Expression"
unlist(gregexpr("\\$",str2))
#[1] 2 6
A.K.
----- Original Message -----
From: Data Analytics Corp. <[email protected]>
To: "[email protected]" <[email protected]>
Cc:
Sent: Monday, January 7, 2013 4:22 PM
Subject: [R] pattern matching
Hi,
I have a simple question. Suppose I have a string "x$Expensive". I want to
find the position of the $ in this string; i.e., I want a function that returns
2. I tried grep, regexpr, etc with no luck, unless I'm just using them
incorrectly. Any suggestions?
Thanks,
Walt
________________________
Walter R. Paczkowski, Ph.D.
Data Analytics Corp.
44 Hamilton Lane
Plainsboro, NJ 08536
________________________
(V) 609-936-8999
(F) 609-936-3733
[email protected]
www.dataanalyticscorp.com
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
[email protected] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
