You might consider using the sqldf package.
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Sent from my phone. Please excuse my brevity.
Martin Batholdy <batho...@googlemail.com> wrote:
>Hi,
>
>
>I need to aggregate rows of a data.frame by computing the mean for rows
>with the same factor-level on one factor-variable;
>
>here is the sample code:
>
>
>x <- data.frame(rep(letters,2), rnorm(52), rnorm(52), rnorm(52))
>
>aggregate(x, list(x[,1]), mean)
>
>
>Now my problem is, that the actual data-set is much bigger (120 rows
>and approximately 100.000 columns) – and it takes very very long
>(actually at some point I just stopped it).
>
>Is there anything that can be done to make the aggregate routine more
>efficient?
>Or is there a different approach that would work faster?
>
>
>Thanks for any suggestions!
>
>______________________________________________
>R-help@r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
