Hello,
Try the following.
tapply(Value, floor(Lat), FUN = mean)
69 70
0.1805381 0.1617072
Hope this helps,
Rui Barradas
Em 11-12-2012 11:17, Swagath Navin escreveu:
Dear all,
I have a big file containing latitude points(-10 to 80) and
corresponding values.
Example data
Lat=c(69.48134, 69.49439, 69.50736, 69.52026, 69.52438, 69.53308,
69.53746, 69.54365, 69.54582, 69.6884, 69.69272, 69.998, 70.00055,
70.00106, 70.00295, 70.00308, 70.00363, 70.00427, 70.00665, 70.00906,
70.01049, 70.01053, 70.01075, 70.01208, 70.01236, 70.01418, 70.01452,
70.01646, 70.01983, 70.0209, 70.02298, 70.02386, 70.02533, 70.02534,
70.02856, 70.0291, 70.02983, 70.03091, 70.03267, 70.03423)
Value=c(0.18917075, 0.18856758, 0.1877328, 0.18664664, 0.18871901,
0.18528864, 0.18797649, 0.18999862, 0.1836383, 0.15414046, 0.18542965,
0.13914858, 0.1654665, 0.12885736, 0.18935319, 0.1912378, 0.14910094,
0.17590007, 0.18369354, 0.12546185, 0.16096813, 0.18851039,
0.14388486, 0.19098477, 0.17252013, 0.12965086, 0.12256515,
0.18159349, 0.15608113, 0.18742996, 0.13858418, 0.16865459,
0.19058037, 0.12531143, 0.19189732, 0.12019097, 0.1790819, 0.15086053,
0.18607724, 0.13330366)
dframe=data.frame(Lat, Value)
i would like to find latitudinal mean such that my output looks like
the below:
Lat Value
69 0.18
70 0.16
I am thankful for any ideas how to perform this or which function i
should look into.
Thanks a lot for your time,
Cheers,
Navin
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