Hello,
Try the following.
m[ , sapply(1:ncol(m), function(j) sapply("B", `%in%`, m[[1 , j]])),
drop=F ]
Hope this helps,
Rui Barradas
Em 04-12-2012 21:16, Asis Hallab escreveu:
Dear R users,
I have a matrix composed of lists:
m <- matrix( list(), nrow=1, ncol=3 )
m[[ 1, 1 ]] <- list("A", "B")
m[[ 1, 2 ]] <- list("A", "C")
m[[ 1, 3 ]] <- list("A", "B")
and want to get the sub-matrix where cells contain "B".
But
m[ , "B" %in% m[ 1, ], drop=F ]
as well as
m[ , "B" %in% m[ 1, ][], drop=F ]
return empty matrices.
Any ideas, hints and help will be very much appreciated!
Kind regards!
Josef
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