This is probably as good a way as any way for this kind of problem.
First define a binary operator:
> "%^%" <- function(x, n)
with(eigen(x), vectors %*% (values^n * t(vectors)))
Your toy example then becomes
> m <- matrix(c(1, 0.4, 0.4, 1), nrow = 2)
> m
[,1] [,2]
[1,] 1.0 0.4
[2,] 0.4 1.0
> m %^% (-0.5)
[,1] [,2]
[1,] 1.0680744 -0.2229201
[2,] -0.2229201 1.0680744
Bill Venables
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-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of jmrossbach
Sent: Sunday, 27 April 2008 11:05 PM
To: [email protected]
Subject: [R] Raising a matrix to the (-1/2) power.
Hi, I need to raise a correlation matrix; R; to the negative one half
power.
i.e. I need to find R^(-1/2)
eg: if R=[{1,.4},{.4,1}], then R^(-1/2)=[{1.0681,-.2229},
{-.2229,1.0681}]where matrix=[{row1},{row2}]
And are there any built in functions to do this? mtx.exp doesn't work
because it's not raised to a positive integer
Thank you so much.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
