Hi, I am encountering a difficulty I don't understand. Be patient, I'm very new to analysis of variance.
If I load this data: example12_7=read.table("http://msemac.redwoods.edu/~darnold/math15/data/chapter12/example12_7.dat",header=TRUE) The run the oneway.test: oneway.test(time~drug,data=example12_7,var.equal=TRUE) I get these results: data: time and drug F = 4.1881, num df = 2, denom df = 16, p-value = 0.03445 Now, I've done the problem by hand and this result agrees with my calculations. Now I try aov and get these results: res1 <- aov(time~drug,data=example12_7) summary(res1) Df Sum Sq Mean Sq F value Pr(>F) drug 1 7.96 7.964 2.417 0.138 Residuals 17 56.01 3.294 Note these do not agree with above. However, if I enter the data by hand: Drug1=c(7.3,8.2,10.1,6.0,9.5) Drug2=c(7.1,10.6,11.2,9.0,8.5,10.9,7.8) Drug3=c(5.8,6.5,8.8,4.9,7.9,8.5,5.2) boxplot(Drug1,Drug2,Drug3) Then create a dataframe: d=stack(list(Drug1=Drug1,Drug2=Drug2,Drug3=Drug3)) And run aov again: res=aov(values~ind,data=d) summary(res) I get these results: Df Sum Sq Mean Sq F value Pr(>F) ind 2 21.98 10.991 4.188 0.0345 * Residuals 16 41.99 2.624 Which completely agree with my calculations. What's going on? Thanks. D. -- View this message in context: http://r.789695.n4.nabble.com/Analysis-of-Variance-tp4651352.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.