Hello,
I don't know if this is it, do you want a 4 digit year or month-yy? The
following function returns month-yy.
fun <- function(x, format = "%B-%y"){
fmt <- format
x <- as.Date(paste("01", x, sep = "-"), format = paste("%d", fmt,
sep = "-"))
m <- as.integer(format(x, "%m"))
y <- as.integer(format(x, "%y"))
y <- ifelse(9 <= m & m <= 12, y + 1, y)
format(as.Date(paste(y, m, 1), "%y %m %d"), fmt)
}
x <- Sys.Date() + 30*(-12:12)
x <- format(x, "%B-%y")
fun(x)
I don't believe it's hard to change to 4 digit year, just change the
return format to "%Y" (last line of code).
Hope this helps,
Rui Barradas
Em 24-11-2012 21:01, nick pardikes escreveu:
If I have data (below) and need some help in figuring out how I can change the
values of my date column, so that a year will be from September-August? So the
year
1990 = September 89-August 90; 1991
= September 90-August 91, etc...
I was trying to use the if() function, but am unable to figure it out. I
basically need to change the years associated with September-December to the
following year. Any
help would be greatly appreciated. Otherwise I will have to power through
it and do it all manually in excel. I am sorry that I do not have the
original data associated with this posting, nor any R code with it. I really do
not have a clue how to even start designating the new year.
head(mydata)
class(mydata)
"data.frame"
site date precipitation temp_max temp_min
1 Castle Peak January-70 0 32 18
2 Castle Peak January-70 0 39 9
3 Castle Peak January-70 0 34 5
4 Castle Peak January-70 0 30 7
5 Castle Peak January-70 0 40 6
6 Castle Peak January-70 0 45 10
Thank you in advance and please let me know what else I can include to help
solve this issue. this is my first posting on R-help.
Nick Pardikes
PhD Student
Program in Ecology, Evolution and Conservation Biology
University of Nevada, Reno
303-550-1072
http://wolfweb.unr.edu/homepage/npardikes/MySite/Welcome.html
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