Hello,
You can do what you want, but the coding of factors starts at 1 not at 0.
dat <- read.table(text="
V1 V2 V3
1 sun moon stars
2 stars moon sun
3 cat dog catdog
4 dog moon sun
5 bird plane superman
6 1000 dog 2000
", header = TRUE)
levs <- unique(unlist(dat))
dat$V1 <- factor(dat$V1, levels = levs)
dat$V2 <- factor(dat$V2, levels = levs)
dat$V3 <- factor(dat$V3, levels = levs)
str(dat)
'data.frame': 6 obs. of 3 variables:
$ V1: Factor w/ 11 levels "sun","stars",..: 1 2 3 4 5 6
$ V2: Factor w/ 11 levels "sun","stars",..: 7 7 4 7 8 4
$ V3: Factor w/ 11 levels "sun","stars",..: 2 1 9 1 10 11
Hope this helps,
Rui Barradas
Em 24-11-2012 07:33, Brian Feeny escreveu:
To clarify on my previous post, here is a representation of what I am trying to
accomplish:
I would like every unique value in either column to be assigned a number so
like so:
V1 V2 V3
1 sun moon stars
2 stars moon sun
3 cat dog catdog
4 dog moon sun
5 bird plane superman
6 1000 dog 2000
Level Value
sun -> 0
stars -> 1
cat -> 2
dog -> 3
bird -> 4
1000 -> 5
moon -> 6
plane -> 7
catdog -> 8
superman -> 9
2000 -> 10
etc
etc
so internally its represented as:
V1 V2 V3
1 0 6 1
2 1 6 0
3 2 3 8
4 3 6 0
5 4 7 9
6 5 3 10
does this make sense? I am hoping there is a way to accomplish this.
Brian
On Nov 23, 2012, at 11:42 PM, Brian Feeny <bfe...@mac.com> wrote:
I am trying to make it so two columns with similar data use the same internal
numbers for same factors, here is the example:
read.csv("test.csv",header =FALSE,sep=",")
V1 V2 V3
1 sun moon stars
2 stars moon sun
3 cat dog catdog
4 dog moon sun
5 bird plane superman
6 1000 dog 2000
data <- read.csv("test.csv",header =FALSE,sep=",")
str(data)
'data.frame': 6 obs. of 3 variables:
$ V1: Factor w/ 6 levels "1000","bird",..: 6 5 3 4 2 1
$ V2: Factor w/ 3 levels "dog","moon","plane": 2 2 1 2 3 1
$ V3: Factor w/ 5 levels "2000","catdog",..: 3 4 2 4 5 1
as.numeric(data$V1)
[1] 6 5 3 4 2 1
as.numeric(data$V2)
[1] 2 2 1 2 3 1
as.factor(data$V1)
[1] sun stars cat dog bird 1000
Levels: 1000 bird cat dog stars sun
as.factor(data$V2)
[1] moon moon dog moon plane dog
Levels: dog moon plane
So notice "dog" is 4 in V1, yet its 1 in V2. Is there a way, either on import,
or after, to have factors computed for both columns and assigned
the same internal values?
Brian
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and provide commented, minimal, self-contained, reproducible code.