Hello,
Your function fun2 (in fact both of them) changes a _copy_ of df1, not
df1 itself. To have a copy of the output of fun2 you need to assign the
value of fun2 outside it.
df2 <- fun2(df1)
Now df2 has what you want. (If I understand it well.)
Hope this helps,
Rui Barradas
Em 17-11-2012 15:41, Omphalodes Verna escreveu:
> Dear list!
>
> I would like to write a function to transform matrix, which is input argument
> of a written function. It is easy with new matrix (see below), but my idea is
> to transform input argument (matrix) of function without any additional
> matrixes. Here is an example:
>
> fun1 <- function(xy) {
> xy <- cbind(xy[,1], xy[,2], xy[,1] + xy[,2])
> return(xy)
> }
>
> df1 <- matrix(c(1,2,3,1,2,3), ncol = 2)
> fun1(df1)
>
> fun2 <- function(xy) {
> xy <- cbind(xy[,1], xy[,2], xy[,1] + xy[,2])
> return(invisible(xy))
> }
>
> fun2(df1)
> df1
>> should be
> [,1] [,2] [,3]
> [1,] 1 1 2
> [2,] 2 2 4
> [3,] 3 3 6
>
> Thanks to all for help,
> OV
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>
>
>
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