HI, Try this:
lapply(mylist,function(x) {recode(x[,2],"'QUE'='QC';'Quebec'='QC'") return(x)}) #$df1 # a prov #1 1 QUE #2 2 QUE #3 3 QUE #4 4 QUE #5 5 QUE #6 6 BC #7 7 BC #8 8 BC #9 9 BC #10 10 BC #$df2 # a prov #1 1 Quebec #2 2 Quebec #3 3 Quebec #4 4 Quebec #5 5 Quebec #6 6 AB #7 7 AB #8 8 AB #9 9 AB #10 10 AB A.K. ----- Original Message ----- From: Simon Kiss <sjk...@gmail.com> To: r-help@r-project.org Cc: Sent: Thursday, November 8, 2012 10:06 PM Subject: [R] using lapply with recode Hello: Forgive me, this is surely a simple question but I can't figure it out, having consulted the help archives and "Data Manipulation With R" (Spector). I have a list of 11 data frames with one common variable in each (prov). I'd like to use lapply to go through and recode one particular level of that common variable. I can get the recode to work, but it only returns the variable that has been recoded. I need the whole data frame with the recoded variable. Thank you for your help. Reproducible data and my current code are below. ####Sample Data mylist<-list(df1=data.frame(a=seq(1,10,1), prov=c(rep('QUE', 5), rep('BC', 5))), df2=data.frame(a=seq(1,10,1), prov=c(rep('Quebec', 5), rep('AB', 5)))) str(mylist) ###My current code lapply(mylist, function(x) { recode(x$prov, "'QUE'='QC' ; 'Quebec'='QC'") } ) ********************************* Simon J. Kiss, PhD Assistant Professor, Wilfrid Laurier University 73 George Street Brantford, Ontario, Canada N3T 2C9 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.