Or
ti <- aggregate(dataframename[paste0("y", 1:3)],
by=dataframename["aggregationvar"],
sum,na.rm=TRUE)
which gives you all results in one data.frame.
Jan
"MacQueen, Don" <macque...@llnl.gov> schreef:
Many ways. Here is one:
### supposing you have y1, y2, and y3 in your data frame
for (i in 1:3) {
yi <- paste('y',i,sep='')
ti <- aggregate(dataframename[[yi]],
by=data.frame(dataframename$aggregationvar),
sum,na.rm=TRUE)
assign( paste('ti',i,sep='') , ti, '.GlobalEnv')
}
Or if you happen to think using assign() is bad form you can store each ti
in a list().
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/1/12 4:32 AM, "bchr" <bochrist...@web.de> wrote:
Hey everybody,
I am looking for a way to loop commands over several variables in a
dataframe. Basically I want to do something like this:
ti1<-aggregate(dataframename$y1,
by=data.frame(dataframename$aggregationvar),
sum,na.rm=TRUE)
This works fine as it is but i want to do it for several variables thereby
generating several tix. I tried with a for-loop but the problem was that I
could neither find a way combine my indexnumber i (1 ... x) with the y or
ti
(as for example in Stata I could do by writing y`i') nor did it work
using
a vector of string variables ("y1", ... "yx") and looping over that
(while
using yx also as a name for the target dataframe instead of tix - i
would'nt
mind that).
Preferably I would be looking for a solution that can do without any of
the
apply functions (yes, I know they are more R-like, but frankly, I don't
get
the logic behind them, so for the time being I would prefer another way)
Tanks very much for your help
Bernhard
--
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