Is this what you want:
> x <- read.table(text = " Mi RBN RBF nDB
> nX
+ 3 2.6225979 0.53132756 -0.80599902 -1.4471864 -0.5705269
+ 10 0.4818746 -1.72143092 -2.19579027 2.0118824 -0.5705269
+ 12 2.8519611 1.88298265 0.09614617 0.6282549 -0.5705269
+ 20 0.6347834 -0.36977583 0.63255683 1.3200687 -0.5705269", header = TRUE)
>
> extract <- c("Mi", "nX")
> x[, extract]
Mi nX
3 2.6225979 -0.5705269
10 0.4818746 -0.5705269
12 2.8519611 -0.5705269
20 0.6347834 -0.5705269
On Tue, Oct 30, 2012 at 10:09 AM, alex_123 <deepak.j...@gmail.com> wrote:
> hello , I am new user in R . I have datafile (class = data.frame) which has
> 825 columns with unique column name i want extract 200 selected column from
> datafile how can I do this?
> my datafile look like..
> Mi RBN RBF nDB nX
> 3 2.6225979 0.53132756 -0.80599902 -1.4471864 -0.5705269
> 10 0.4818746 -1.72143092 -2.19579027 2.0118824 -0.5705269
> 12 2.8519611 1.88298265 0.09614617 0.6282549 -0.5705269
> 20 0.6347834 -0.36977583 0.63255683 1.3200687 -0.5705269
>
>
> I want to extract data with unique name of column , by "Mi","RBF" etc . I
> have stored character vector of desired column names. eg aa =
> c("Mi","RBF",..)
>
>
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/help-extract-data-using-column-names-tp4647869.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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