On 12-10-23 6:56 PM, Brian wrote:
Hi List,why are the results of the two bits of below code different? > sapply(1:ncol(d.f), function(i) mode(d.f[,i])) [1] "character" "character" "numeric" "numeric" "numeric" "numeric" [7] "numeric" "numeric" "numeric" "numeric" "numeric" "numeric" [13] "numeric" "numeric" "character" > apply(d.f, 2, mode) stn time gre000z0 prestas0 tre200s0 ure200s0 "character" "character" "character" "character" "character" "character" usp200s0 fve010z0 dkl010z0 chron CO_sync CO2_dry_sync "character" "character" "character" "character" "character" "character" CH4_dry_sync H2O_sync wd.bin "character" "character" "character" I am a bit vexed. I thought those two would be equivalent.
As the man page says, apply coerces a dataframe to a matrix before doing the calculations. In a matrix, all the columns are the same type.
Duncan Murdoch ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
