Hi, If the criteria is to pick which among the following states are the top 2 contributors for each candidate, dat1<-read.table(text="
AL AR CA NY Doug 250 250 250 NA Jennifer 20 340 300 100 Michele 250 500 250 60 Obama 15 45 520 600 ",header=TRUE,stringsAsFactors=FALSE,sep="") #for Obama apply(dat1,1,function(x,n) x[which(rank(x)>length(x)-n)],n=2)[4] #$Obama # CA NY #520 600 Your question was to list the states where Obama has higher amount received compared to ?? A.K. ----- Original Message ----- From: noobmin <pseudov...@hotmail.com> To: r-help@r-project.org Cc: Sent: Tuesday, October 23, 2012 7:41 AM Subject: Re: [R] How to use tapply with more than one variables grouped I believe that previously could not be understood. To facilitate'll give you an example. Assuming my table is presented below with the amount received from each candidate for president in a particular country state. AL AR CA NY Doug 250 250 250 NA Jennifer 20 340 300 100 Michele 250 500 250 60 Obama 15 45 520 600 I would like to list the states where Obama has higher amount received (ie in CA and NY) and also the number of states, in this case 2. How to do this? Thanks -- View this message in context: http://r.789695.n4.nabble.com/How-to-use-tapply-with-more-than-one-variables-grouped-tp4646948p4647111.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.