Hello,
There's no function cut2() but it's not very difficult to write one.
I've named your data example 'dat', it saves keystrokes.
Try the following.
dat <- structure(...etc...)
cut2 <- function(x, g = 0){
cut(x, breaks = c(-Inf, seq(min(x), max(x), length.out = g)))
}
fun <- function(x) {
ct <- cut2(x, g = 4)
factor(ct, levels = levels(ct), labels=1:4)
}
tmp <- sapply(dat[-1], fun)
colnames(tmp) <- paste("quartile", colnames(tmp), sep="_")
dat2 <- cbind(dat, tmp)
str(dat2)
Hope this helps,
Rui Barradas
Em 17-10-2012 15:23, Charles Determan Jr escreveu:
Greetings R users,
My goal is to generate quartile groups of each variable in my data set. I
would like each experiment to have its designated group added as a
subsequent column. I can accomplish this individually with the following
code:
brks <- with(data_variables,
cut2(var2, g=4))
#I don't want the actual numbers, I need a numbered group
data$test1=factor(brks, labels=1:4)
However, I cannot get a loop to work nor can I get a loop to add the
columns with an appropriate name (ex. quartile_variable). I have tried
multiple different ways but can't seem to get it to work. I think it would
begin something like this:
for(i in 11:ncol(survival_data_variables)){
brks=as.data.frame(with(survival_data_variables,
cut2(survival_data_variables[,i], g=4)))
Any assistance would be sincerely appreciated. I would like the final data
set to have the following layout:
ID var1 var2 var3 var4 quartile var1
quartile var2 quartile var3 quartile var4
Here is a subset of my data to work with:
structure(list(ID = c(11112L, 11811L, 12412L, 12510L, 13111L,
20209L, 20612L, 20711L, 21510L, 22012L), var1 = c(106, 107,
116, 67, 76, 146, 89, 62, 65, 116), var2 = c(0, 0, 201,
558, 526, 555, 576, 0, 531, 649), var3 = c(70.67, 81.33,
93.67, 84.33, 52, 74, 114, 101, 80.33, 91.33), var4 = c(136,
139, 142, 138, 140, 140, 136, 139, 140, 139)), .Names = c("ID",
"var1", "var2", "var3", "var4"), row.names = c(NA,
10L), class = "data.frame")
Regards,
Charles
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