?cut
try this:
> seq1 = seq(0, 95, by = 5)
> seq2 = seq(100, 1000, by = 100)
> Bands = c(seq1, seq2)
> Prices = sample(1:1000, 200, replace=F)
> table(cut(Prices, breaks = Bands))
(0,5] (5,10] (10,15] (15,20] (20,25]
(25,30] (30,35] (35,40]
1 2 1 1 0
2 1 1
(40,45] (45,50] (50,55] (55,60] (60,65]
(65,70] (70,75] (75,80]
1 1 1 1 1
1 1 0
(80,85] (85,90] (90,95] (95,100] (100,200]
(200,300] (300,400] (400,500]
1 2 0 1 22
20 17 22
(500,600] (600,700] (700,800] (800,900] (900,1e+03]
25 20 16 18 20
>
>
>
On Tue, Oct 16, 2012 at 4:37 PM, jcrosbie <ja...@crosb.ie> wrote:
> I would like to create a frequency table with custom bands.
>
> seq1 = seq(0, 100, by = 5)
> seq2 = seq(100, 1000, by = 100)
> Bands = c(seq1, seq2)
> Prices = sample(1:1000, 200, replace=F)
>
> How would I go about find the frequency of prices within each band?
>
>
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/frequency-table-with-custom-bands-tp4646413.html
> Sent from the R help mailing list archive at Nabble.com.
>
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--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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