Hi, On Sun, Oct 14, 2012 at 11:23 AM, Shant Ch <sha1...@yahoo.com> wrote: > n=10 > x1<-(1:n)/n > y1<-rnorm(n,x1^2,1) > m=20 > x2<-(1:m)/m > > The value of y2 will be rnorm (m, x2^2,1) if none of the elements of x2 is > same as x1, but for every same elements in x1 and x2, the value of y2 will be > same as y1. I know the following is correct, but for large vectors, this > won't work efficiently as this is taking longer time. Can you please let me > know how to write the following more efficiently.
Sounds like y2 <- rnorm (m, x2^2,1) y2 <- ifelse(x2==x1, y1, y2) Best, Ista > ------------------- > y2<-rep(0,m) > for(i in 1:m) > { > for (j in 1:n) > { > if(x2[i]==x1[j] > { > y2[i]=y1[j] > } > else > { > y2[i]=rnorm(1,x2[i]^2,1); > } > } > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.