Hi, You can also try this: set.seed(1) dat1<-data.frame(id=rep(c(1,2,3),c(30,20,25)),value=rnorm(75,15)) dat2<-data.frame(stack(lapply(split(dat1,dat1$id),FUN=function(x) 1:nrow(x))),value=dat1[,2]) colnames(dat2)[1:2]<-c("seq1","id") dat2$seq1 # [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 #[26] 26 27 28 29 30 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 #[51] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 A.K.
----- Original Message ----- From: bibek sharma <mbhpat...@gmail.com> To: r-help@r-project.org Cc: Sent: Tuesday, October 9, 2012 2:54 PM Subject: [R] Qustion about Creating a sequence of vector Hello R User, I have a data set where subject( Id) are frequently measured. For example, the size of the data set is 75 by 2 and has following frequency distribution. id freq 1 30 2 20 3 25 I want to create a variable (say seq) containing sequential count for each id. I mean variable seq should be as ( 1,2,..,30, 1,2,...,20, 1,2,...,25) I use following code but did not work. Any suggestion is much appreciated.. sim<-rep(NA, 90) for (i in 1:3){ d[i]<-seq(1,a[i,2],by=1) sim[i]<-as.vector(c(d[i]) } Thank you, Bibek ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.