Dear Christiane, I found the code and output that you attached difficult to read, but I see at least one error: I'm not sure why you think that Anova() takes a contrasts argument. It doesn't; contrasts is an argument to lm(). See ?Anova and ?lm.
Here's a reproducible example that shows that you get the same tests from Anova() and drop1(): ---------------- snip ------------ > # proper "type III" tests: > mod.1 <- lm(conformity ~ fcategory*partner.status, data=Moore, + contrasts=list(fcategory=contr.poly, partner.status=contr.sum)) > drop1(mod.1, .~.,test="F") Single term deletions Model: conformity ~ fcategory * partner.status Df Sum of Sq RSS AIC F value Pr(>F) <none> 817.76 142.50 fcategory 2 36.019 853.78 140.44 0.8589 0.431492 partner.status 1 239.562 1057.33 152.06 11.4250 0.001657 ** fcategory:partner.status 2 175.489 993.25 147.25 4.1846 0.022572 * --- Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 > Anova(mod.1, type=3) Anova Table (Type III tests) Response: conformity Sum Sq Df F value Pr(>F) (Intercept) 5752.8 1 274.3592 < 2.2e-16 *** fcategory 36.0 2 0.8589 0.431492 partner.status 239.6 1 11.4250 0.001657 ** fcategory:partner.status 175.5 2 4.1846 0.022572 * Residuals 817.8 39 --- Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 > # hypotheses not sensible: > mod.2 <- lm(conformity ~ fcategory*partner.status, data=Moore) > drop1(mod.2, .~.,test="F") Single term deletions Model: conformity ~ fcategory * partner.status Df Sum of Sq RSS AIC F value Pr(>F) <none> 817.76 142.50 fcategory 2 89.674 907.44 143.18 2.1383 0.13147 partner.status 1 2.201 819.97 140.62 0.1050 0.74767 fcategory:partner.status 2 175.489 993.25 147.25 4.1846 0.02257 * --- Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 > Anova(mod.2, type=3) Anova Table (Type III tests) Response: conformity Sum Sq Df F value Pr(>F) (Intercept) 984.14 1 46.9348 3.436e-08 *** fcategory 89.67 2 2.1383 0.13147 partner.status 2.20 1 0.1050 0.74767 fcategory:partner.status 175.49 2 4.1846 0.02257 * Residuals 817.76 39 --- Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 ---------------- snip ------------ I hope that this helps, John ----------------------------------------------- John Fox Senator McMaster Professor of Social Statistics Department of Sociology McMaster University Hamilton, Ontario, Canada > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] > On Behalf Of C. Weiner > Sent: Sunday, October 07, 2012 7:37 PM > To: r-help@r-project.org > Subject: [R] Why do I get different results for type III anova using the > drop1 or Anova command? > > Dear experts, > > I just noticed that I get different results conducting type III anova > using drop1 or the Anova command from the car package. I suppose I made > a mistake and hope you can offer me some help. I have no idea where I > got wrong and would be very grateful for explaination as R is new > terrain for me. > If I run the commands in line, they produce the same results. But if I > run them in seperate windows, they produce different results. > > What I did in easy words: > Opened R prompt, ran parts 0 and 1-> got result 1 > Opened new R prompt, ran parts 0 and 2 ->got result 2, ran part 1 > following part 2, got result 2a > > Why are the results different when they are run seperately and why do > the commands produce the same results when running one after the other? > Which results can I rely on? I based my script on: > http://mcfromnz.wordpress.com/2011/03/0 ... explained/ > <http://mcfromnz.wordpress.com/2011/03/02/anova-type-iiiiii-ss- > explained/> > but I surely made mistakes. > > Thanks for help. > Kind regards, > Christiane > > > > #0 > library(car) > P<-read.table("rhoPgegenrhoAgewichtet-mit Befruchtungssystem0912.txt", > sep="\t",dec=",", header=T,encoding="latin1") > summary(P) > str(P) > > #1 > modD3 <- lm(P$rhoPug ~ P$rhoAg*P$dprime*P$Befruchtungssystem, data=P) > > Anova(modD3,contrasts=list(rhoAg=contr.sum, dprime=contr.poly), > type="III") ###liefert dieses Ergebnis, wenn der Befehl als erster läuft > #Response: P$rhoPug > # Sum Sq Df F value Pr(>F) > #(Intercept) 0.07719 1 4.5075 0.03530 * > #P$rhoAg 0.00687 1 0.4014 0.52730 > #P$dprime 0.00176 1 0.1029 0.74882 > #P$Befruchtungssystem 0.00250 1 0.1461 0.70280 > #P$rhoAg:P$dprime 0.00931 1 0.5439 0.46193 > #P$rhoAg:P$Befruchtungssystem 0.00001 1 0.0004 0.98343 > #P$dprime:P$Befruchtungssystem 0.00108 1 0.0630 0.80214 > #P$rhoAg:P$dprime:P$Befruchtungssystem 0.00206 1 0.1205 0.72893 > #Residuals 2.70584 158 > > > #2 > options(contrasts = c("contr.sum","contr.poly")) #liefert ein anderes > Ergebnis als der Befehl oben, wenn der obere Befehl NICHT gelaufen ist > modD3 <- lm(P$rhoPug ~ P$rhoAg*P$dprime*P$Befruchtungssystem, data=P) > drop1(modD3,.~.,test="F") # type III SS and F Test > P$rhoPug ~ P$rhoAg * P$dprime * P$Befruchtungssystem > Df Sum of Sq RSS AIC F value Pr(F) > <none> 2.7058 -667.35 > P$rhoAg 1 0.0131973 2.7190 -668.54 0.7706 0.3814 !! > P$dprime 1 0.0002240 2.7061 -669.34 0.0131 0.9091 !! > P$Befruchtungssystem 1 0.0025022 2.7083 -669.20 0.1461 0.7028 !! > P$rhoAg:P$dprime 1 0.0283677 2.7342 -667.62 1.6565 0.2000 !! > P$rhoAg:P$Befruchtungssystem 1 0.0000074 2.7058 -669.35 0.0004 0.9834 > P$dprime:P$Befruchtungssystem 1 0.0010790 2.7069 -669.29 0.0630 0.8021 > P$rhoAg:P$dprime:P$Befruchtungssystem 1 0.0020641 2.7079 -669.22 0.1205 > 0.7289 > > > #2a (command is the same as in 1, but results are different if the > command is run after the one above) > Anova(modD3,contrasts=list(Befruchtungssystem="contr.sum", > dprime="contr.poly"), type="III") #liefert in nachstehend nach dem > 2.Befehl dieses Ergebnis > #Response: P$rhoPug #also jetzt dasselbe wie drop1, aber nicht dasselbe, > das > #der exakt gleich Befehl alleine geliefert hätte. Was > #stimmt den nun? Wo liegt mein Fehler? > # Sum Sq Df F value Pr(>F) > #(Intercept) 0.06877 1 4.0158 0.04679 * > #P$rhoAg 0.01320 1 0.7706 0.38136 > #P$dprime 0.00022 1 0.0131 0.90909 > #P$Befruchtungssystem 0.00250 1 0.1461 0.70280 > #P$rhoAg:P$dprime 0.02837 1 1.6565 0.19997 > #P$rhoAg:P$Befruchtungssystem 0.00001 1 0.0004 0.98343 > #P$dprime:P$Befruchtungssystem 0.00108 1 0.0630 0.80214 > #P$rhoAg:P$dprime:P$Befruchtungssystem 0.00206 1 0.1205 0.72893 > #Residuals 2.70584 158 > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.