Hi, You can try this: list2<-lapply(1:dim(my.df.cast)[3],function(i) my.df.cast[,,i,]) names(list2)<-unlist(dimnames(my.df.cast)[3]) list2$May #, , variable = tmax # # name #year Alf Que # 2011 18 16 # 2012 18 16
#, , variable = tmin # # name #year Alf Que # 2011 12 11 # 2012 12 11 list2$May[,,"tmax"] # name #year Alf Que # 2011 18 16 # 2012 18 16 A.K. ----- Original Message ----- From: anto.r <anto.ra...@gmail.com> To: r-help@r-project.org Cc: Sent: Thursday, October 4, 2012 11:57 AM Subject: Re: [R] convert multi dimensional array to list Hi Michael thanks! That was the option if I kept it an array. The list format with $ sign since it leaves me feeling that the names are there and can be easily accessed. Why would you rather not use the $ sign? I use R-Studio and there names can be selected from a drop-down list, I have found it easier but that could be my lack of proper training in R. Cheers Anto -- View this message in context: http://r.789695.n4.nabble.com/convert-multi-dimensional-array-to-list-tp4645011p4645036.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
