Dear people of the help list I am drying to analyze my data using the 'lmer' function and I keep having problems.
This is the model: > fm1<-lmer(dbh~spec+scheme+(1|Plot),data=d, REML=FALSE). I analyse tree size (dbh) of 3 different species (spec) and 3 planting schemes (scheme). I have 5 plots, which I hope to model as a random factor. (However, the subsequent output is based on some simplified dummy data, which is based on only two plots and ha only few observations). No I do: > anova(fm1) and I get some output, which I don't understand. Looks like this: Analysis of Variance Table Df Sum Sq Mean Sq F value spec 2 6.098 3.0490 0.6142 scheme 2 13.161 6.5803 1.3255 The problems I have are: (1) How can I get the P-values? (2) How can I get the overall model statistic? Than I do: > summary(fm1) and get: Linear mixed model fit by maximum likelihood Formula: dbh ~ spec + scheme + (1 | Plot) Data: d AIC BIC logLik deviance REMLdev 147.2 157 -66.6 133.2 125.8 Random effects: Groups Name Variance Std.Dev. Plot (Intercept) 0.0000 0.0000 Residual 4.9644 2.2281 Number of obs: 30, groups: Plot, 2 Fixed effects: Estimate Std. Error t value (Intercept) 6.9074 0.9424 7.329 specCED 0.3859 1.0265 0.376 specTAB 0.8585 0.9828 0.874 schemeMON 0.6572 0.9554 0.688 schemePRO -1.0344 1.1259 -0.919 Correlation of Fixed Effects: (Intr) spcCED spcTAB schMON specCED -0.537 specTAB -0.529 0.500 schemeMON -0.588 0.002 -0.072 schemePRO -0.565 0.064 0.063 0.510 What is this? What does it tell me? The statistics help advised me to do a second model, like this: > fm2<-lmer(dbh~scheme+(1|Plot),data=d,REML=FALSE) > anova(fm1,fm2) But why would I compare the two models? What I get is: Data: d Models: fm2: dbh ~ scheme + (1 | Plot) fm1: dbh ~ spec + scheme + (1 | Plot) Df AIC BIC logLik Chisq Chi Df Pr(>Chisq) fm2 5 143.96 150.97 -66.982 fm1 7 147.21 157.01 -66.602 0.7584 2 0.6844 What does this mean? Why Chi? Finally I would like to do some LSD post hoc tests, but I have no idea how to do it. In the end I would like to be able to report something like: 'DBH differed significantly between, species, planting schemes, and plots (Fx,xx = X; P = X). DBH of species 1 was significantly larger than DBH of species 2 (LSD post hoc test, P = X)'. I greatly appreciate any suggestions! Thank You a lot for Your help! Kind regards, Judith PS. the complete output is attached. XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX Judith Riedel ETH Zurich Institute of Agricultural Sciences Applied Entomology Schmelzbergstrasse 9/LFO 8092 Zurich Switzerland Tel: ++41 44 632 3923 Fax: ++41 44 632 1171 judith.rie...@ipw.agrl.ethz.ch<mailto:judith.rie...@ipw.agrl.ethz.ch> http://www.em.ipw.agrl.ethz.ch
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