Users forget how much is an OS service. This is OS X not R being slow.

On a recent Linux box it takes about 90s.

But at least you can easily parallelize it: see ?pvec in package parallel for one way to do this (and one way not to).

If the file contain a high proportion of duplicates, making a factor and converting the levels will help.

On 27/09/2012 18:24, Fisher Dennis wrote:
R 2.15.1
OS X.7.4

Colleagues,

I have a large dataset (27773536 records, the file is several GB) that contains 
a column of date / time entries in the format:
        "2/1/2011 13:25:01"   
I need to convert these to numeric values (ideally in seconds; the origin 
[e.g., 1970-01-01] is not important).

I am using:
         as.numeric(strptime(DATA$DATADTM, "%m/%d/%Y %H:%M:%S"))
It takes 21 minutes to execute this step on a dual quad-core Mac with 12 GB RAM 
(it is appreciably slower on other Mac's including a new i5 iMac).

Are there other time formatting functions or strategies that would be faster?

Sample data:
        TIMECOL <- rep("2/1/2011 13:25:01", 100)

Any tips would be appreciated.

Dennis

Dennis Fisher MD
P < (The "P Less Than" Company)
Phone: 1-866-PLessThan (1-866-753-7784)
Fax: 1-866-PLessThan (1-866-753-7784)
www.PLessThan.com

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Brian D. Ripley,                  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
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