Hello,
You should have kept it in the R-Help list, the odds of having more
answers would be greater.
There was a bug in the loop. It should be cleanDataSets[[i]] not
cleanDataSets[i].
Anyway, I've simplified it a bit.
fls <- list.files(pattern = "*.csv")
files <- lapply(fls, read.csv, header=T)
good <- lapply(files, complete.cases)
cleanDataSets <- lapply(seq_along(fls), function(i) files[[i]][
good[[i]], ])
Hope this helps,
Rui Barradas
Em 25-09-2012 15:29, Dimitris r escreveu:
hi,
steps taken :
files<-lapply(list.files(),read.csv,header=T)
numberOfFiles<-length(list.files())
good<-lapply(files,complete.cases)
cleanDataSets<-list()
for (i in 1:numberOfFiles){
cleanDataSets[i]=files[[i]][good[[i]],]
}
with this loop for some reason i get only the first column from each data
frame from the list
if want to retrieve the only one data frame from the list i can do like
this:
files<-lapply(list.files(),read.csv,header=T)
good<-complete.cases(files[[1]])
files[[1]][good,]
thanks in advance
Dimitris
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