Hi I do not understand your point.
actually lm(y~x) is the same as lm(y~x+1) You can specify a model without intercept by lm(y~x-1) you can even do lm(y~log(x)) But log(intercept) does not have sense. You will get an intercept which is a number and you can consider it log(intercept) exp(intercept) intercept^2 Regards Petr > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- > project.org] On Behalf Of Cheryl Johnson > Sent: Sunday, September 23, 2012 11:26 PM > To: r-help@r-project.org > Subject: [R] How to Write a Model in R that has the Log taken of the > Intercept > > Hi, > > I know that +1 is used to specify an intercept in a R model. An example > of this would be: y~x+1 > > If I want to have a model where the log of the intercept is taken, the > equation y~x+log(1) will not take the log of the intercept. > > Any suggestions on how to take the log of the intercept will be > appreciated. > > Thanks > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
