On 12-09-07 4:49 PM, Tinus Sonnekus wrote:
Hi All,
I have a data set wit three size classes (pico, nano and micro) and 12
different sites (Seamounts). I want to produce a table with the mean and
standard deviation values for each site.
Seamount Pico Nano Micro Total_Ch
1 Off_Mount 1 0.0691 0.24200 0.00100 0.31210
2 Off_Mount 1 0.0938 0.00521 0.02060 0.11961
3 Off_Mount 1 0.1130 0.20000 0.06620 0.37920
4 Off_Mount 1 0.0864 0.15900 0.22300 0.46840
5 Off_Mount 1 0.0262 0.04570 0.00261 0.07451
6 Off_Mount 2 0.0314 0.17400 0.12800 0.33340
Something like this could work:
library(tables)
tabular( Seamount ~ (Pico + Nano + Micro)*mean, data=SChla)
There are lots of variations, e.g. if you want the size classes as rows
and the Seamounts as columns,
tabular( (Pico + Nano + Micro) ~ Seamount*mean, data=SChla)
It will also output LaTeX tables if you ask for them.
Duncan Murdoch
I tried the following script but get an error message
*Error in results[i, "u.Pico", "u.Nano", "u.Micro"] <- sapply(z, mean) : *
* incorrect number of subscripts *
The code I used:
*SChla <- read.csv("SM_Chla_data.csv")*
*sm <- as.character(unique(SChla$Seamount))*
*
*
*results <-
matrix(NA,nrow=length(sm),ncol=6,dimnames=list(sm,c("u.Pico","u.Nano","u.Micro","sd.Pico","sd.Nano","sd.Micro")))
*
*
*
*for (i in sm){*
*z <- subset(SChla, Seamount==i, select=c(Pico, Nano, Micro))*
*results[i,"u.Pico","u.Nano","u.Micro"] <- sapply(z, mean)*
*results[i,"sd.Pico","sd.Nano","sd.Micro"] <- sapply(z, sd)*
*}*
*
*
*print(results)*
Please can some one advise me how to fix the error or maybe have an
alternative solution I will appreciate it.
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