Hello, Yet another alternative.
library(plyr)
dfr <- ldply(strsplit(c("a,1", "b,2", "c,3"), ","), identity)
str(dfr)
#dfr$V2 <- as.numeric(dfr$V2)
So, if the op was about conversion to df, the answer is yes.
Rui Barradas
Em 30-08-2012 18:14, David Winsemius escreveu:
On Aug 30, 2012, at 9:44 AM, Sam Steingold wrote:* Sam Steingold <[email protected]> [2012-08-30 08:56:17 -0400]: Is there a way for an apply-type function to return a data frame? the closest thing I think of is foo <- as.data.frame(t(sapply(...))) names(foo) <- c(....)alas, this has a problem of creating a "homogeneous" data frame, i.e., all the columns are numbers or characters, because the function passed to sapply returns c(....) andc(1,2,"a")[1] "1" "2" "a" e.g.,as.data.frame(t(sapply(c("a,1","b,2","c,3"),function (n) strsplit(n,",")[[1]])))V1 V2 a,1 a 1 b,2 b 2 c,3 c 3 'data.frame': 3 obs. of 2 variables: $ V1: Factor w/ 3 levels "a","b","c": 1 2 3 ..- attr(*, "names")= chr "a,1" "b,2" "c,3" $ V2: Factor w/ 3 levels "1","2","3": 1 2 3 ..- attr(*, "names")= chr "a,1" "b,2" "c,3" I wanted the V1 column to be a string, and V2 to be a number. (I know stringsAsFactors=FALSE would replace factors with strings, but I need a string and a number) I could, of course, do ret$V2 <- as.numeric(ret$V2) but this would mean a double conversion: from number to string first (by c()) and then back.It is starting as a 'string' ('character' in R parlance) so you will need to coerce it to "numeric" at some point:Consider this alternate route: > do.call(rbind, strsplit(c("a,1","b,2","c,3"), ",") ) [,1] [,2] [1,] "a" "1" [2,] "b" "2" [3,] "c" "3" > as.data.frame( do.call(rbind, strsplit(c("a,1","b,2","c,3"), ",") ) ) V1 V2 1 a 1 2 b 2 3 c 3> str( as.data.frame( do.call(rbind, strsplit(c("a,1","b,2","c,3"), ",") ) , stringsAsFactors=FALSE) )'data.frame': 3 obs. of 2 variables: $ V1: chr "a" "b" "c" $ V2: chr "1" "2" "3"
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