On 2012-08-28 10:34, Duncan Murdoch wrote:
On 28/08/2012 1:12 PM, Liviu Andronic wrote:
Dear all
Suppose the object below:
require(Hmisc)
require(plyr)
x <- dlply(iris, .(Species), describe)
How can I print the object without displaying the attributes? I
inspected ?print and ?print.default with no luck.
Assign a class to the object, and write a print method for it.
For example, this doesn't quite do what you want, but it's a start:
print.noattributes <- function(x, ...) {
attributes(x) <- NULL
print(x)
}
class(x) <- "noattributes"
x
It loses some attributes that you probably want to keep (e.g. the
names), but otherwise works on your example.
Duncan Murdoch
It seems that class "listof" also works:
class(x) <- "listof"
x
Peter Ehlers
x
$setosa
x[, "Sepal.Length"]
n missing unique Mean .05 .10 .25 .50 .75
50 0 15 5.006 4.40 4.59 4.80 5.00 5.20
.90 .95
5.41 5.61
4.3 4.4 4.5 4.6 4.7 4.8 4.9 5 5.1 5.2 5.3 5.4 5.5 5.7 5.8
Frequency 1 3 1 4 2 5 4 8 8 3 1 5 2 2 1
% 2 6 2 8 4 10 8 16 16 6 2 10 4 4 2
$versicolor
x[, "Sepal.Length"]
n missing unique Mean .05 .10 .25 .50 .75
50 0 21 5.936 5.045 5.380 5.600 5.900 6.300
.90 .95
6.700 6.755
lowest : 4.9 5.0 5.1 5.2 5.4, highest: 6.6 6.7 6.8 6.9 7.0
$virginica
x[, "Sepal.Length"]
n missing unique Mean .05 .10 .25 .50 .75
50 0 21 6.588 5.745 5.800 6.225 6.500 6.900
.90 .95
7.610 7.700
lowest : 4.9 5.6 5.7 5.8 5.9, highest: 7.3 7.4 7.6 7.7 7.9
attr(,"split_type")
[1] "data.frame"
attr(,"split_labels")
Species
1 setosa
2 versicolor
3 virginica
Regards
Liviu
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