Hello,

I'm being lazy, but the following works.

r = 3 ; set.seed(1)
v <- matrix(c(rnorm(40)),10,4)

result <- vector("list", r*ncol(v))
ires <- 0

for (j in 1:4){
    for (i in 1:r){
        x <- t(v[,j]^(i)*v[,1:4]^((r-(4-1)):r))
        #print(x)
        ires <- ires + 1
        result[[ ires ]] <- x
        }
    }

result <- do.call(rbind, result)
dim(result)

Lazy because there might be a way of avoiding the loops. If this is just an example, is your real problem big?

Hope this helps,

Rui Barradas

Em 22-08-2012 14:23, bilelsan escreveu:
Dear Ruser,
Below, the deal (you can copy paste):

r=3 ; set.seed(1)
v <- matrix(c(rnorm(40)),10,4)
for (j in 1:4){
     for (i in 1:r){
         x <- t(v[,j]^(i)*v[,1:4]^((r-(4-1)):r))
         print(x)
         }
     }

How to reach to " x " " row bind " inside or outside (preferred) of the
loop.
To obtain at the end something like:
x
matrix( , 12*4, 10)

Any help or advice is very welcome
Many regards
Bilel



--
View this message in context: 
http://r.789695.n4.nabble.com/rbind-in-a-loop-with-elements-tp4640976.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to