You probably mean grepl('[a-zA-Z]', x)
Regards,
Yihui
--
Yihui Xie <xieyi...@gmail.com>
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Mon, Aug 6, 2012 at 3:29 PM, Liviu Andronic <landronim...@gmail.com> wrote:
> On Mon, Aug 6, 2012 at 6:42 PM, Bert Gunter <gunter.ber...@gene.com> wrote:
>> nzchar(x) & !is.na(x)
>>
>> No?
>>
>
> It doesn't work for what I need:
>> x
> [1] "a10" "b8" "c9" "d2" "e3" "f4" "g1" "h7" "i6" "j5" "k"
> "l" "m" "n"
> [15] "o" "p" "q" "r" "s" "t" "u" "v" "w" "x" "y"
> "z" "1" "2"
> [29] "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" "13"
> "14" "15" "16"
> [43] "17" "18" "19" "20" "21" "22" "23" "24" "25" "26"
>> nzchar(x) & !is.na(x)
> [1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE
> TRUE TRUE TRUE TRUE
> [18] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE
> TRUE TRUE TRUE TRUE
> [35] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE
> TRUE TRUE TRUE TRUE
> [52] TRUE
>
>
> I need to have TRUE when an element contains a letter, and FALSE when
> an element contains only numbers. The above returns TRUE for the
> entire vector.
>
> Regards
> Liviu
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