Thank you for the answer, but I did´n find the solution. I'm a bit lost,
cos I am a beginner in R. I hope you can give me a little bit more help.
2012/7/29 jholtman [via R] <ml-node+s789695n4638270...@n4.nabble.com>
> Try this: You had some 'indexing' problems. You were accessing the
> columns of the dataframe incorrectly. You are also accessing 'list'
> so you might want to review the Intro to R on indexing:
>
> > datos.mx1 <- read.table('
> http://r.789695.n4.nabble.com/file/n4638257/PETmx1.csv',head=TRUE,sep=';')
>
> > datos.min <- read.table('
> http://r.789695.n4.nabble.com/file/n4638257/PETmin.csv',head=TRUE,sep=';')
>
>
> >
> > superior <- NULL
> > inferior <- NULL
> > LC <- NULL
> > LF <- NULL
> >
> >
> > for (i in 3:6){
>
> + superior[[i]] <- 23+(datos.mx1[[i]]-23)*0.33;
> + inferior[[i]] <- 18+(datos.min[[i]]-18)*0.33;
> + }
>
> >
> > #Until here everything is ok, but the next loop issues an error. I must
>
> > #multiply the results of each weather station with a constant.
>
> >
> > for (i in 3:6){
>
> +
> + LF[[i]] <- 1.26086956521739*superior[[i]]
> + LC[[i]] <- 0.722222222222222*inferior[[i]]
> + }
> > str(LF)
> List of 6
> $ : NULL
> $ : NULL
> $ : num [1:1826] 21.1 21.7 23.5 23.5 23.7 ...
> $ : num [1:1826] 25.4 23.5 24.8 25 24.5 ...
> $ : num [1:1826] 23.3 24 24.7 24.7 24.9 ...
> $ : num [1:1826] 21.8 22.6 23.5 23.5 22.8 ...
> > str(LC)
> List of 6
> $ : NULL
> $ : NULL
> $ : num [1:1826] 7.83 8.5 8.21 7.83 8.28 ...
> $ : num [1:1826] 9.07 9.76 8.54 8.07 9.35 ...
> $ : num [1:1826] 8.66 8.95 8.61 7.61 9.12 ...
> $ : num [1:1826] 8.07 8.69 8.07 7.85 8.23 ...
>
> On Sun, Jul 29, 2012 at 9:59 AM, Domi <[hidden
> email]<http://user/SendEmail.jtp?type=node&node=4638270&i=0>>
> wrote:
>
> > Hello erverybody,
> >
> > I have a problem with my second for-loop.
> >
> > 1. First i read the tables.
> >
> > datos.mx1 <- read.table('PETmx1.csv',head=TRUE,sep=';')
> > datos.min <- read.table('PETmin.csv',head=TRUE,sep=';')
> >
> > http://r.789695.n4.nabble.com/file/n4638257/PETmx1.csv PETmx1.csv
> > http://r.789695.n4.nabble.com/file/n4638257/PETmin.csv PETmin.csv
> >
> > names(datos.mx1)
> >
> > "Fecha" "Mes" "Serra.da.Foladoira"
> > "Santiago" "Sergude" "Rio.Do.Sol"
> >
> > You find in the first column the date and in the second only the month.
> The
> > other columns contain the temperature of the respective weather
> stations.
> >
> > 2. My aim is to calculate thresholds for each weather station.
> >
> > superior <- NULL
> > inferior <- NULL
> > LC <- NULL
> > LF <- NULL
> >
> >
> > for (i in 3:6){
> > superior[i] <- 23+(datos.mx1[i]-23)*0.33;
> > inferior[i] <- 18+(datos.min[i]-18)*0.33;
> > }
> >
> > #Until here everything is ok, but the next loop issues an error. I must
> > multiply the results of each weather station with a constant.
> >
> > for (i in 3:6){
> >
> > LF[i] <- 1.26086956521739*superior[[i]];
> > LC[i] <- 0.722222222222222*inferior[[i]]
> > }
> >
> >
> > The error is: "Number of items to replace is not a multiple of
> replacement
> > length".
> >
> >
> > I hope someone can help me. I thank you very much.
> >
> > Best regards,
> >
> > Domi
> >
> >
> >
> >
> >
> >
> > --
> > View this message in context:
> http://r.789695.n4.nabble.com/Error-in-for-loop-tp4638257.html
> > Sent from the R help mailing list archive at Nabble.com.
> >
> > ______________________________________________
> > [hidden email]
> > <http://user/SendEmail.jtp?type=node&node=4638270&i=1>mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
> ______________________________________________
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