Not sure, but maybe check the name of the column(s) you are retrieving
you may get a NULL value if the column name is misspelled
R example:
## --------------------------------------
df <- data.frame(
"Publication" = 1991:2000,
"Reference" = LETTERS[1:10] )
df[ 2, "References" ]
# NULL
## Notice the extra 's'
## --------------------------------------
If that does not fix your error, can you send us the output from
head(x)
# and
dput(head(x))
So we have an idea what your table looks like?
All the best
Julien
________________________________________
From: [email protected] [[email protected]] On Behalf Of
Sri krishna Devarayalu Balanagu [[email protected]]
Sent: 01 August 2012 08:58
To: [email protected]
Subject: [R] Why the result is coming as NULL?
Why the result is coming as NULL. Can anyone help. I want to find the outliers
for a reference
setwd("D:/AZ")
library("RODBC")
cdb_cnct <- odbcConnectExcel("Book1.xls")
cdb_frame <- sqlFetch(cdb_cnct, "Sheet1")
odbcClose(cdb_cnct)
rm(cdb_cnct)
x<- cdb_frame$Publication >=1990 & cdb_frame$Publication <=2012
invalid <- cdb_frame[!x, c("Reference")]
invalid
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