Hello,
Sorry, but I don't understand, there's nothing specific in the search
pattern, it searches for the negation of digits and replaces them for "".
string = "\t\t\t\t\t<span class=\"compliment-count profile\">11</span>"
string = c(string, "\t\t\t\t\t<span class=\"compliment-count
profile\">1234</span>")
string = c(string, "\t\t\t\t\t<span class=\"compliment-count
profile\">9876543210</span>")
gsub("[^[:digit:]]", "", string)
[1] "11" "1234" "9876543210"
Have you tried with other numbers?
Rui Barradas
Em 31-07-2012 21:25, Shelby McIntyre escreveu:
Good solution for when the number is "11", however, I don't know that the number is going
to be "11", next time
it might be 1231 or 1,254 or some other number. So, this isn't really a
solution for my situation.
On Jul 31, 2012, at 12:31 AM, Rui Barradas wrote:
Hello,
Try the following.
string <- "\t\t\t\t\t<span class=\"compliment-count profile\">11</span>"
gsub("[^[:digit:]]", "", string)
Then use as.numeric or as.integer.
Hope this helps,
Rui Barradas
Em 31-07-2012 01:19, Shelby McIntyre escreveu:
Below is the string to parse and return the embedded number = "11"
string = "\t\t\t\t\t<span class=\"compliment-count profile\">11</span>"
On Jul 29, 2012, at 3:00 AM, r-help-requ...@r-project.org wrote:
char
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