On Mon, Jul 30, 2012 at 8:49 AM, Bert Gunter <gunter.ber...@gene.com> wrote: > Not necessarily. If the OP really meant the R list() structure, then > is.element does not apply.
Perhaps... x <- list(1:5, "a", `+`, rnorm, NULL, list(letters)) letters %in% x # Works -- vectorized, mostly false, but the "a" is there, per below "a" %in% x # Works, true 1 %in% x # Works, false 1:5 %in% x # Works -- vectorized, false list(1:5) %in% x # Works, true `+` %in% x # Error NULL %in% x # logical(0) so it seems is.element / %in% [chacun son gout] works with "vectors" (in a rather broad sense of that word) I'm still trying to understand quite how this one works though: list(letters) %in% x # Works -- false: this one surprised me! identical(list(letters), x[[6]]) # True Best, Michael ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
