You could have googled "R solve equation", and would have easily reached
http://r.789695.n4.nabble.com/R-solve-equation-td882585.html and would have in there found something like this: > z <- matrix(c(-8.313,-1,1), ncol=1) > polyroot(z) [1] 3.42626+0i -2.42626+0i > p<-polyroot(z) > p^2-p [1] 8.313+0i 8.313+0i On 27.07.2012, at 12:30, Paul Smith wrote: > On Thu, Jul 26, 2012 at 9:48 PM, Diviya Smith <diviya.sm...@gmail.com> wrote: >> Hi there, >> >> I would like to solve a simple equation in R >> >> a^2 - a = 8.313 >> >> There is no real solution to this problem but I would like to get an >> approximate numerical solution. Can someone suggest how I can set this up? > > Since your equation is a quadratic one, why do not you use the formula > to obtain its roots? > > You can find the formula at: > > http://en.wikipedia.org/wiki/Quadratic_equation > > Paul > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
