Hello,

I'm not familiar with package urca but your problem seems to be in the access of a list member. The operator '$' is an alternative to '[[', and you are right, the latter is recommended programmatically.

Try something along the lines of the following.

VARrow[[ "varresult" ]][[ "Liabilities" ]]

And note that you can use numbers instead of the members' names.
str(VARrow) would give the structure of the variable and the appropriate numbers to use (just count).

Hope this helps,

Rui Barradas

Em 27-07-2012 09:57, Rmillan escreveu:
Hi everyone,

I'm working with the Vector Autoregressive Model (VAR), and it seems like
the ur.ca package provides the best
function for this purpose.
My problem is, that I don't know how to extract a certain value from the
output without using the variables names.
I was hoping that this could be done by using numerical value, e.g. [1],
instead of writing for instance $Liabilities. The reason why I want to do
this is, that this would help me to automize the process, since I may not
use the variable Liabilities next time.

Here is an example when the process works, but I have to do it manually by
typing in $Liabilities

VARrow<-VAR(data,p=1,type="const")
row<-VARrow$varresult$Liabilities$coefficient
row[1]

Liabilities.l1
     0.06898797

It would be nice if I could type in e.g. colnames(data)[1] instead of
Liabilities (because colnames(data)[1] referes to Liabilites) but this
command just says the value is NULL instead 0.06898797....

Any help is much appriciated



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