This looks like a homework trap set up to catch those trying to use facilities like Rhelp.
f = exp(x^2-y+z^(-1))= exp(x^2) * exp(1/z)/exp(y) To maximize clearly needs biggest x (37), smallest y (2) and a z that makes exp(1/z) big -- 0. Except that you'll get Inf etc. Actually, several of the optimization tools in R don't do too badly on this (about half of the routines in optplus (the R-forge version of optimx) get reasobable answers, but there are some oddities depending on starting values. JN On 07/08/2012 06:00 AM, r-help-requ...@r-project.org wrote: > Message: 64 > Date: Sun, 8 Jul 2012 10:15:34 +0100 > From: Raghuraman Ramachandran <optionsra...@gmail.com> > To: R Project Help <r-help@r-project.org> > Subject: [R] Help in Optimization of a function > Message-ID: > <CADgEnDmRbxPoCHSDGghAeVUJxGcbZCAz6Bs99Ty_t=ffesa...@mail.gmail.com> > Content-Type: text/plain > > guRus! > > I have a function f = exp(x^2-y+(1/z)) > > Also, x can take values from 1 to 37, y from 2 to 20 and Z from -13 to 51. > > How can I find the maximum of f using any of the optimization functions > please? > > Is there a way to store the possible values of x, y and Z in a single > variable like in a List or in a multi-dimensional array? > > Thanks for your help > Raghu > > [[alternative HTML version deleted]] > > > > ------------------------------ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
