Hi, If you want to assign a vector to every element of a list, vec1<-11:20
list1<-split(LETTERS[1:10],1:length(LETTERS[1:10])) list2<-lapply(1:10,function(x) vec1) or, list3<-lapply(list1,function(x) list1=vec1) or list4<-list() vec2<-1:5 list4[1:length(list1)]<-list(vec2) # if you want to assign each element of vector to each element of list (assuming both have the same lengths), vec1<-11:20 list1<-split(LETTERS[1:10],1:length(LETTERS[1:10])) newlist<-split(vec1,1:length(vec1)) A.K. ----- Original Message ----- From: Spencer Maynes <[email protected]> To: [email protected] Cc: Sent: Monday, July 2, 2012 6:16 PM Subject: [R] Assigning a vector to every element of a list. I have a vector d of unknown length, and a list b of unknown length. I would like to replace every element of b with d. Simply writing b<-d does not work as R tries to fit every element of d to a different element of d, and b<-rep(d,length(b)) does not work either as it makes a list of length length(d)*length(b) not a list of length(b). I know how to do this with a for loop, but I feel that there has to be a more efficient way. Any suggestions? [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
